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131222120420000 = 255417237096121
BaseRepresentation
bin11101110101100010000111…
…110111111101001010100000
3122012121201020012012011102002
4131311202013313331022200
5114144420400311420000
61143030335423543132
736432325320654101
oct3565420767751240
9565551205164362
10131222120420000
11388a1a97029265
121287388675aaa8
13582b267934cbc
1424592824523a8
1510285c624c8d5
hex775887dfd2a0

131222120420000 has 360 divisors, whose sum is σ = 343081415851020. Its totient is φ = 49379880960000.

The previous prime is 131222120419877. The next prime is 131222120420021. The reversal of 131222120420000 is 24021222131.

131222120420000 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 30 ways, for example, as 105926169697936 + 25295950722064 = 10292044^2 + 5029508^2 .

It is a Harshad number since it is a multiple of its sum of digits (20).

It is an unprimeable number.

It is a polite number, since it can be written in 59 ways as a sum of consecutive naturals, for example, 21438016940 + ... + 21438023060.

Almost surely, 2131222120420000 is an apocalyptic number.

131222120420000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131222120420000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (171540707925510).

131222120420000 is an abundant number, since it is smaller than the sum of its proper divisors (211859295431020).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131222120420000 is an equidigital number, since it uses as much as digits as its factorization.

131222120420000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9894 (or 9854 counting only the distinct ones).

The product of its (nonzero) digits is 384, while the sum is 20.

Adding to 131222120420000 its reverse (24021222131), we get a palindrome (131246141642131).

The spelling of 131222120420000 in words is "one hundred thirty-one trillion, two hundred twenty-two billion, one hundred twenty million, four hundred twenty thousand".