1312221401 has 4 divisors (see below), whose sum is σ = 1313565492. Its totient is φ = 1310877312.

The previous prime is 1312221389. The next prime is 1312221403. The reversal of 1312221401 is 1041222131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1041222131 = 1447 ⋅719573.

It can be written as a sum of positive squares in 2 ways, for example, as 1003305625 + 308915776 = 31675^2 + 17576^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1312221401 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1312221401.

It is not an unprimeable number, because it can be changed into a prime (1312221403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 670580 + ... + 672533.

It is an arithmetic number, because the mean of its divisors is an integer number (328391373).

Almost surely, 2^1312221401 is an apocalyptic number.

It is an amenable number.

1312221401 is a deficient number, since it is larger than the sum of its proper divisors (1344091).

1312221401 is an equidigital number, since it uses as much as digits as its factorization.

1312221401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1344090.

The product of its (nonzero) digits is 96, while the sum is 17.

The square root of 1312221401 is about 36224.5966299143. The cubic root of 1312221401 is about 1094.8023109406.

Adding to 1312221401 its reverse (1041222131), we get a palindrome (2353443532).

The spelling of 1312221401 in words is "one billion, three hundred twelve million, two hundred twenty-one thousand, four hundred one".