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13122223101157 is a prime number
BaseRepresentation
bin1011111011110100000101…
…1100100101010011100101
31201110110202021211101020211
42332331001130211103211
53204443303103214112
643524133245455421
72523022630666312
oct276750134452345
951413667741224
1013122223101157
1141aa1159326a5
12157b211b71571
13742560601c51
143351946ddd09
1517b5148be0a7
hexbef417254e5

13122223101157 has 2 divisors, whose sum is σ = 13122223101158. Its totient is φ = 13122223101156.

The previous prime is 13122223101079. The next prime is 13122223101167. The reversal of 13122223101157 is 75110132222131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12608400790561 + 513822310596 = 3550831^2 + 716814^2 .

It is a cyclic number.

It is not a de Polignac number, because 13122223101157 - 215 = 13122223068389 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13122223101167) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561111550578 + 6561111550579.

It is an arithmetic number, because the mean of its divisors is an integer number (6561111550579).

Almost surely, 213122223101157 is an apocalyptic number.

It is an amenable number.

13122223101157 is a deficient number, since it is larger than the sum of its proper divisors (1).

13122223101157 is an equidigital number, since it uses as much as digits as its factorization.

13122223101157 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5040, while the sum is 31.

Adding to 13122223101157 its reverse (75110132222131), we get a palindrome (88232355323288).

The spelling of 13122223101157 in words is "thirteen trillion, one hundred twenty-two billion, two hundred twenty-three million, one hundred one thousand, one hundred fifty-seven".