Base | Representation |
---|---|
bin | 1011111011110100000101… |
… | …1100100101010011100101 |
3 | 1201110110202021211101020211 |
4 | 2332331001130211103211 |
5 | 3204443303103214112 |
6 | 43524133245455421 |
7 | 2523022630666312 |
oct | 276750134452345 |
9 | 51413667741224 |
10 | 13122223101157 |
11 | 41aa1159326a5 |
12 | 157b211b71571 |
13 | 742560601c51 |
14 | 3351946ddd09 |
15 | 17b5148be0a7 |
hex | bef417254e5 |
13122223101157 has 2 divisors, whose sum is σ = 13122223101158. Its totient is φ = 13122223101156.
The previous prime is 13122223101079. The next prime is 13122223101167. The reversal of 13122223101157 is 75110132222131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12608400790561 + 513822310596 = 3550831^2 + 716814^2 .
It is a cyclic number.
It is not a de Polignac number, because 13122223101157 - 215 = 13122223068389 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13122223101167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561111550578 + 6561111550579.
It is an arithmetic number, because the mean of its divisors is an integer number (6561111550579).
Almost surely, 213122223101157 is an apocalyptic number.
It is an amenable number.
13122223101157 is a deficient number, since it is larger than the sum of its proper divisors (1).
13122223101157 is an equidigital number, since it uses as much as digits as its factorization.
13122223101157 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5040, while the sum is 31.
Adding to 13122223101157 its reverse (75110132222131), we get a palindrome (88232355323288).
The spelling of 13122223101157 in words is "thirteen trillion, one hundred twenty-two billion, two hundred twenty-three million, one hundred one thousand, one hundred fifty-seven".
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