Base | Representation |
---|---|
bin | 11000011100010010… |
… | …10100000110010110 |
3 | 1020212111210002000002 |
4 | 30032021110012112 |
5 | 203333242141114 |
6 | 10010034451302 |
7 | 643116032246 |
oct | 141611240626 |
9 | 36774702002 |
10 | 13122224534 |
11 | 5624176571 |
12 | 2662733b32 |
13 | 13117c7303 |
14 | 8c6aa3b26 |
15 | 51c0467de |
hex | 30e254196 |
13122224534 has 4 divisors (see below), whose sum is σ = 19683336804. Its totient is φ = 6561112266.
The previous prime is 13122224513. The next prime is 13122224539. The reversal of 13122224534 is 43542222131.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 43542222131 = 43 ⋅1012609817.
It is a junction number, because it is equal to n+sod(n) for n = 13122224497 and 13122224506.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13122224539) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3280556132 + ... + 3280556135.
It is an arithmetic number, because the mean of its divisors is an integer number (4920834201).
Almost surely, 213122224534 is an apocalyptic number.
13122224534 is a deficient number, since it is larger than the sum of its proper divisors (6561112270).
13122224534 is an equidigital number, since it uses as much as digits as its factorization.
13122224534 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6561112269.
The product of its digits is 11520, while the sum is 29.
Adding to 13122224534 its reverse (43542222131), we get a palindrome (56664446665).
The spelling of 13122224534 in words is "thirteen billion, one hundred twenty-two million, two hundred twenty-four thousand, five hundred thirty-four".
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