Base | Representation |
---|---|
bin | 10011000110000110100… |
… | …101100111011111011111 |
3 | 11122110002002010212202121 |
4 | 103012012211213133133 |
5 | 132444413044031221 |
6 | 2442454341403411 |
7 | 163543052514121 |
oct | 23060645473737 |
9 | 4573062125677 |
10 | 1312223033311 |
11 | 466568769013 |
12 | 192398a09567 |
13 | 9698551c228 |
14 | 47724a63211 |
15 | 2420204ea41 |
hex | 131869677df |
1312223033311 has 2 divisors, whose sum is σ = 1312223033312. Its totient is φ = 1312223033310.
The previous prime is 1312223033293. The next prime is 1312223033333. The reversal of 1312223033311 is 1133303222131.
It is a weak prime.
It is an emirp because it is prime and its reverse (1133303222131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1312223033311 - 237 = 1174784079839 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1312223033371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656111516655 + 656111516656.
It is an arithmetic number, because the mean of its divisors is an integer number (656111516656).
Almost surely, 21312223033311 is an apocalyptic number.
1312223033311 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312223033311 is an equidigital number, since it uses as much as digits as its factorization.
1312223033311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 1312223033311 its reverse (1133303222131), we get a palindrome (2445526255442).
The spelling of 1312223033311 in words is "one trillion, three hundred twelve billion, two hundred twenty-three million, thirty-three thousand, three hundred eleven".
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