Base | Representation |
---|---|
bin | 11101110101100010010011… |
… | …001111110100001101010101 |
3 | 122012121201201111020000111102 |
4 | 131311202103033310031111 |
5 | 114144421243133133044 |
6 | 1143030410401315445 |
7 | 36432333125531315 |
oct | 3565422317641525 |
9 | 565551644200442 |
10 | 131222311224149 |
11 | 388a2084800242 |
12 | 1287391a635b85 |
13 | 582b29831c772 |
14 | 245929d91d445 |
15 | 10285d7d8c24e |
hex | 7758933f4355 |
131222311224149 has 2 divisors, whose sum is σ = 131222311224150. Its totient is φ = 131222311224148.
The previous prime is 131222311224097. The next prime is 131222311224223. The reversal of 131222311224149 is 941422113222131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 130819951899025 + 402359325124 = 11437655^2 + 634318^2 .
It is a cyclic number.
It is not a de Polignac number, because 131222311224149 - 240 = 130122799596373 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131222311224049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65611155612074 + 65611155612075.
It is an arithmetic number, because the mean of its divisors is an integer number (65611155612075).
Almost surely, 2131222311224149 is an apocalyptic number.
It is an amenable number.
131222311224149 is a deficient number, since it is larger than the sum of its proper divisors (1).
131222311224149 is an equidigital number, since it uses as much as digits as its factorization.
131222311224149 is an evil number, because the sum of its binary digits is even.
The product of its digits is 41472, while the sum is 38.
The spelling of 131222311224149 in words is "one hundred thirty-one trillion, two hundred twenty-two billion, three hundred eleven million, two hundred twenty-four thousand, one hundred forty-nine".
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