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1312225003633 is a prime number
BaseRepresentation
bin10011000110000110101…
…101001000100001110001
311122110002012211222112111
4103012012231020201301
5132444414100104013
62442454451525321
7163543105331365
oct23060655104161
94573065758474
101312225003633
11466569894385
121923995b9841
1396985a5bcbb
14477250172a5
15242022dd73d
hex13186b48871

1312225003633 has 2 divisors, whose sum is σ = 1312225003634. Its totient is φ = 1312225003632.

The previous prime is 1312225003627. The next prime is 1312225003651. The reversal of 1312225003633 is 3363005222131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1106718728049 + 205506275584 = 1052007^2 + 453328^2 .

It is a cyclic number.

It is not a de Polignac number, because 1312225003633 - 217 = 1312224872561 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1312225003595 and 1312225003604.

It is not a weakly prime, because it can be changed into another prime (1312225003603) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656112501816 + 656112501817.

It is an arithmetic number, because the mean of its divisors is an integer number (656112501817).

Almost surely, 21312225003633 is an apocalyptic number.

It is an amenable number.

1312225003633 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312225003633 is an equidigital number, since it uses as much as digits as its factorization.

1312225003633 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 19440, while the sum is 31.

The spelling of 1312225003633 in words is "one trillion, three hundred twelve billion, two hundred twenty-five million, three thousand, six hundred thirty-three".