13122300554541 has 24 divisors (see below), whose sum is σ = 19237403615040. Its totient is φ = 8617804272000.

The previous prime is 13122300554507. The next prime is 13122300554593. The reversal of 13122300554541 is 14545500322131.

13122300554541 is a `hidden beast` number, since 1 + 3 + 1 + 22 + 30 + 0 + 554 + 54 + 1 = 666.

13122300554541 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 13122300554541 - 2⁹ = 13122300554029 is a prime.

It is a super-2 number, since 2×13122300554541² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13122300554496 and 13122300554505.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13122300553541) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 7781971 + ... + 9316848.

It is an arithmetic number, because the mean of its divisors is an integer number (801558483960).

Almost surely, 2^{13122300554541} is an apocalyptic number.

It is an amenable number.

13122300554541 is a deficient number, since it is larger than the sum of its proper divisors (6115103060499).

13122300554541 is a wasteful number, since it uses less digits than its factorization.

13122300554541 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17100097 (or 17100094 counting only the distinct ones).

The product of its (nonzero) digits is 72000, while the sum is 36.

Adding to 13122300554541 its reverse (14545500322131), we get a palindrome (27667800876672).

The spelling of 13122300554541 in words is "thirteen trillion, one hundred twenty-two billion, three hundred million, five hundred fifty-four thousand, five hundred forty-one".