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13122301121191 is a prime number
BaseRepresentation
bin1011111011110100011000…
…0110001101001010100111
31201110110221201122012121201
42332331012012031022213
53204443433041334231
643524145114023331
72523024566105053
oct276750606151247
951413851565551
1013122301121191
1141aa155981269
12157b234117b47
1374257381b052
143351a0c0cc63
1517b51b681161
hexbef4618d2a7

13122301121191 has 2 divisors, whose sum is σ = 13122301121192. Its totient is φ = 13122301121190.

The previous prime is 13122301121101. The next prime is 13122301121299. The reversal of 13122301121191 is 19112110322131.

It is a weak prime.

It is an emirp because it is prime and its reverse (19112110322131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13122301121191 - 231 = 13120153637543 is a prime.

It is a super-3 number, since 3×131223011211913 (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13122301121101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561150560595 + 6561150560596.

It is an arithmetic number, because the mean of its divisors is an integer number (6561150560596).

Almost surely, 213122301121191 is an apocalyptic number.

13122301121191 is a deficient number, since it is larger than the sum of its proper divisors (1).

13122301121191 is an equidigital number, since it uses as much as digits as its factorization.

13122301121191 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 28.

The spelling of 13122301121191 in words is "thirteen trillion, one hundred twenty-two billion, three hundred one million, one hundred twenty-one thousand, one hundred ninety-one".