Base | Representation |
---|---|
bin | 1011111011110100011000… |
… | …1011100101011100001101 |
3 | 1201110110221211021211222111 |
4 | 2332331012023211130031 |
5 | 3204443433422000331 |
6 | 43524145204144021 |
7 | 2523024614100223 |
oct | 276750613453415 |
9 | 51413854254874 |
10 | 13122302531341 |
11 | 41aa156754783 |
12 | 157b234698011 |
13 | 742573bc2b63 |
14 | 3351a1098b13 |
15 | 17b51b85ddb1 |
hex | bef462e570d |
13122302531341 has 16 divisors (see below), whose sum is σ = 14047528819968. Its totient is φ = 12227538294400.
The previous prime is 13122302531333. The next prime is 13122302531357. The reversal of 13122302531341 is 14313520322131.
It is a cyclic number.
It is not a de Polignac number, because 13122302531341 - 23 = 13122302531333 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13122302531321) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9638905 + ... + 10915726.
It is an arithmetic number, because the mean of its divisors is an integer number (877970551248).
Almost surely, 213122302531341 is an apocalyptic number.
It is an amenable number.
13122302531341 is a deficient number, since it is larger than the sum of its proper divisors (925226288627).
13122302531341 is a wasteful number, since it uses less digits than its factorization.
13122302531341 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 20555372.
The product of its (nonzero) digits is 12960, while the sum is 31.
Adding to 13122302531341 its reverse (14313520322131), we get a palindrome (27435822853472).
The spelling of 13122302531341 in words is "thirteen trillion, one hundred twenty-two billion, three hundred two million, five hundred thirty-one thousand, three hundred forty-one".
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