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1312231233031 is a prime number
BaseRepresentation
bin10011000110000111000…
…100111001011000000111
311122110002122120110122221
4103012013010321120013
5132444422143424111
62442455233233211
7163543212305035
oct23060704713007
94573078513587
101312231233031
11466572359644
1219239b702807
1396987130534
1447725b99555
1524202b1e371
hex13187139607

1312231233031 has 2 divisors, whose sum is σ = 1312231233032. Its totient is φ = 1312231233030.

The previous prime is 1312231233011. The next prime is 1312231233067. The reversal of 1312231233031 is 1303321322131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1312231233031 - 25 = 1312231232999 is a prime.

It is a super-2 number, since 2×13122312330312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1312231232987 and 1312231233005.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1312231233011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656115616515 + 656115616516.

It is an arithmetic number, because the mean of its divisors is an integer number (656115616516).

Almost surely, 21312231233031 is an apocalyptic number.

1312231233031 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312231233031 is an equidigital number, since it uses as much as digits as its factorization.

1312231233031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 1312231233031 its reverse (1303321322131), we get a palindrome (2615552555162).

The spelling of 1312231233031 in words is "one trillion, three hundred twelve billion, two hundred thirty-one million, two hundred thirty-three thousand, thirty-one".