Base | Representation |
---|---|
bin | 10011000110000111000… |
… | …111110100101011100111 |
3 | 11122110002201000110001202 |
4 | 103012013013310223213 |
5 | 132444422343001411 |
6 | 2442455301513115 |
7 | 163543221651545 |
oct | 23060707645347 |
9 | 4573081013052 |
10 | 1312232000231 |
11 | 466572832a99 |
12 | 19239ba1279b |
13 | 9698733b7b9 |
14 | 47725d18d95 |
15 | 24202c2183b |
hex | 131871f4ae7 |
1312232000231 has 4 divisors (see below), whose sum is σ = 1312253271264. Its totient is φ = 1312210729200.
The previous prime is 1312232000173. The next prime is 1312232000243. The reversal of 1312232000231 is 1320002322131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1312232000231 - 214 = 1312231983847 is a prime.
It is a super-2 number, since 2×13122320002312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1312232000291) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10542710 + ... + 10666451.
It is an arithmetic number, because the mean of its divisors is an integer number (328063317816).
Almost surely, 21312232000231 is an apocalyptic number.
1312232000231 is a deficient number, since it is larger than the sum of its proper divisors (21271033).
1312232000231 is an equidigital number, since it uses as much as digits as its factorization.
1312232000231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21271032.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 1312232000231 its reverse (1320002322131), we get a palindrome (2632234322362).
The spelling of 1312232000231 in words is "one trillion, three hundred twelve billion, two hundred thirty-two million, two hundred thirty-one", and thus it is an aban number.
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