Base | Representation |
---|---|
bin | 1011111011110100011101… |
… | …0101111011011111011001 |
3 | 1201110111000011221222211021 |
4 | 2332331013111323133121 |
5 | 3204444003414122223 |
6 | 43524151142002441 |
7 | 2523025241540332 |
oct | 276750725733731 |
9 | 51414004858737 |
10 | 13122322020313 |
11 | 41aa166756070 |
12 | 157b23b116421 |
13 | 742577c577ac |
14 | 3351a38cd289 |
15 | 17b51d40d65d |
hex | bef4757b7d9 |
13122322020313 has 4 divisors (see below), whose sum is σ = 14315260385808. Its totient is φ = 11929383654820.
The previous prime is 13122322020293. The next prime is 13122322020319. The reversal of 13122322020313 is 31302022322131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13122322020313 - 29 = 13122322019801 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13122322020319) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 596469182731 + ... + 596469182752.
It is an arithmetic number, because the mean of its divisors is an integer number (3578815096452).
Almost surely, 213122322020313 is an apocalyptic number.
It is an amenable number.
13122322020313 is a deficient number, since it is larger than the sum of its proper divisors (1192938365495).
13122322020313 is a wasteful number, since it uses less digits than its factorization.
13122322020313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1192938365494.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 13122322020313 its reverse (31302022322131), we get a palindrome (44424344342444).
The spelling of 13122322020313 in words is "thirteen trillion, one hundred twenty-two billion, three hundred twenty-two million, twenty thousand, three hundred thirteen".
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