Base | Representation |
---|---|
bin | 10011000110000111001… |
… | …100111001100111001111 |
3 | 11122110002210112001202002 |
4 | 103012013030321213033 |
5 | 132444423213044101 |
6 | 2442455350222515 |
7 | 163543236164021 |
oct | 23060714714717 |
9 | 4573083461662 |
10 | 1312233331151 |
11 | 466573561a26 |
12 | 1923a0354a3b |
13 | 969876b6522 |
14 | 47726184011 |
15 | 24202dd5d6b |
hex | 131873399cf |
1312233331151 has 2 divisors, whose sum is σ = 1312233331152. Its totient is φ = 1312233331150.
The previous prime is 1312233331069. The next prime is 1312233331163. The reversal of 1312233331151 is 1511333322131.
It is a strong prime.
It is an emirp because it is prime and its reverse (1511333322131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1312233331151 - 226 = 1312166222287 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1312233331051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656116665575 + 656116665576.
It is an arithmetic number, because the mean of its divisors is an integer number (656116665576).
Almost surely, 21312233331151 is an apocalyptic number.
1312233331151 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312233331151 is an equidigital number, since it uses as much as digits as its factorization.
1312233331151 is an evil number, because the sum of its binary digits is even.
The product of its digits is 4860, while the sum is 29.
Adding to 1312233331151 its reverse (1511333322131), we get a palindrome (2823566653282).
The spelling of 1312233331151 in words is "one trillion, three hundred twelve billion, two hundred thirty-three million, three hundred thirty-one thousand, one hundred fifty-one".
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