Base | Representation |
---|---|
bin | 11101110101100011010101… |
… | …111111011010111111000100 |
3 | 122012121211121112021112012020 |
4 | 131311203111333122333010 |
5 | 114144431041314000004 |
6 | 1143031113442123140 |
7 | 36432402643501050 |
oct | 3565432577327704 |
9 | 565554545245166 |
10 | 131223431000004 |
11 | 388a25a98a2432 |
12 | 12873b916504b0 |
13 | 582b416305825 |
14 | 2459368528c60 |
15 | 102865132c8d9 |
hex | 7758d5fdafc4 |
131223431000004 has 96 divisors (see below), whose sum is σ = 350298724478976. Its totient is φ = 37452832341120.
The previous prime is 131223431000003. The next prime is 131223431000023. The reversal of 131223431000004 is 400000134322131.
It is a happy number.
It is not an unprimeable number, because it can be changed into a prime (131223431000003) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 304996257 + ... + 305426199.
It is an arithmetic number, because the mean of its divisors is an integer number (3648945046656).
Almost surely, 2131223431000004 is an apocalyptic number.
131223431000004 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
131223431000004 is an abundant number, since it is smaller than the sum of its proper divisors (219075293478972).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131223431000004 is a wasteful number, since it uses less digits than its factorization.
131223431000004 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 433785 (or 433783 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 24.
Adding to 131223431000004 its reverse (400000134322131), we get a palindrome (531223565322135).
The spelling of 131223431000004 in words is "one hundred thirty-one trillion, two hundred twenty-three billion, four hundred thirty-one million, four", and thus it is an aban number.
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