13122420220403 has 4 divisors (see below), whose sum is σ = 14131837160448. Its totient is φ = 12113003280360.

The previous prime is 13122420220367. The next prime is 13122420220423. The reversal of 13122420220403 is 30402202422131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13122420220403 - 2¹⁰ = 13122420219379 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13122420220423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 504708470003 + ... + 504708470028.

It is an arithmetic number, because the mean of its divisors is an integer number (3532959290112).

Almost surely, 2^{13122420220403} is an apocalyptic number.

13122420220403 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

13122420220403 is a deficient number, since it is larger than the sum of its proper divisors (1009416940045).

13122420220403 is a wasteful number, since it uses less digits than its factorization.

13122420220403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1009416940044.

The product of its (nonzero) digits is 4608, while the sum is 26.

Adding to 13122420220403 its reverse (30402202422131), we get a palindrome (43524622642534).

The spelling of 13122420220403 in words is "thirteen trillion, one hundred twenty-two billion, four hundred twenty million, two hundred twenty thousand, four hundred three".