1312244031431 has 4 divisors (see below), whose sum is σ = 1313005637352. Its totient is φ = 1311482425512.

The previous prime is 1312244031389. The next prime is 1312244031433. The reversal of 1312244031431 is 1341304422131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1312244031431 - 2²² = 1312239837127 is a prime.

It is a super-2 number, since 2×1312244031431² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1312244031394 and 1312244031403.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1312244031433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 380800376 + ... + 380803821.

It is an arithmetic number, because the mean of its divisors is an integer number (328251409338).

Almost surely, 2^{1312244031431} is an apocalyptic number.

1312244031431 is a deficient number, since it is larger than the sum of its proper divisors (761605921).

1312244031431 is an equidigital number, since it uses as much as digits as its factorization.

1312244031431 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 761605920.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 1312244031431 its reverse (1341304422131), we get a palindrome (2653548453562).

The spelling of 1312244031431 in words is "one trillion, three hundred twelve billion, two hundred forty-four million, thirty-one thousand, four hundred thirty-one".