Base | Representation |
---|---|
bin | 1011111011110100111100… |
… | …1010100011001011001111 |
3 | 1201110111100022220101210011 |
4 | 2332331033022203023033 |
5 | 3204444241013123423 |
6 | 43524212150454051 |
7 | 2523031424162341 |
oct | 276751712431317 |
9 | 51414308811704 |
10 | 13122453254863 |
11 | 41aa223840577 |
12 | 157b277064327 |
13 | 7425991b6184 |
14 | 3351b70d1291 |
15 | 17b529bd2b0d |
hex | bef4f2a32cf |
13122453254863 has 2 divisors, whose sum is σ = 13122453254864. Its totient is φ = 13122453254862.
The previous prime is 13122453254837. The next prime is 13122453254879. The reversal of 13122453254863 is 36845235422131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13122453254863 - 225 = 13122419700431 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13122453254263) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561226627431 + 6561226627432.
It is an arithmetic number, because the mean of its divisors is an integer number (6561226627432).
Almost surely, 213122453254863 is an apocalyptic number.
13122453254863 is a deficient number, since it is larger than the sum of its proper divisors (1).
13122453254863 is an equidigital number, since it uses as much as digits as its factorization.
13122453254863 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 4147200, while the sum is 49.
Adding to 13122453254863 its reverse (36845235422131), we get a palindrome (49967688676994).
The spelling of 13122453254863 in words is "thirteen trillion, one hundred twenty-two billion, four hundred fifty-three million, two hundred fifty-four thousand, eight hundred sixty-three".
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