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13122545511191 is a prime number
BaseRepresentation
bin1011111011110101010010…
…1010011110101100010111
31201110111120202111111200012
42332331110222132230113
53204444433122324231
643524225244110435
72523033624303254
oct276752452365427
951414522444605
1013122545511191
1141aa270923076
12157b2a1b3541b
137425b234810c
143351c546842b
1517b532d57e2b
hexbef54a9eb17

13122545511191 has 2 divisors, whose sum is σ = 13122545511192. Its totient is φ = 13122545511190.

The previous prime is 13122545511181. The next prime is 13122545511241. The reversal of 13122545511191 is 19111554522131.

It is a weak prime.

It is an emirp because it is prime and its reverse (19111554522131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13122545511191 is a prime.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13122545511181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561272755595 + 6561272755596.

It is an arithmetic number, because the mean of its divisors is an integer number (6561272755596).

Almost surely, 213122545511191 is an apocalyptic number.

13122545511191 is a deficient number, since it is larger than the sum of its proper divisors (1).

13122545511191 is an equidigital number, since it uses as much as digits as its factorization.

13122545511191 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 54000, while the sum is 41.

The spelling of 13122545511191 in words is "thirteen trillion, one hundred twenty-two billion, five hundred forty-five million, five hundred eleven thousand, one hundred ninety-one".