Base | Representation |
---|---|
bin | 1011111011110101010010… |
… | …1010011110101100010111 |
3 | 1201110111120202111111200012 |
4 | 2332331110222132230113 |
5 | 3204444433122324231 |
6 | 43524225244110435 |
7 | 2523033624303254 |
oct | 276752452365427 |
9 | 51414522444605 |
10 | 13122545511191 |
11 | 41aa270923076 |
12 | 157b2a1b3541b |
13 | 7425b234810c |
14 | 3351c546842b |
15 | 17b532d57e2b |
hex | bef54a9eb17 |
13122545511191 has 2 divisors, whose sum is σ = 13122545511192. Its totient is φ = 13122545511190.
The previous prime is 13122545511181. The next prime is 13122545511241. The reversal of 13122545511191 is 19111554522131.
It is a weak prime.
It is an emirp because it is prime and its reverse (19111554522131) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13122545511191 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13122545511181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561272755595 + 6561272755596.
It is an arithmetic number, because the mean of its divisors is an integer number (6561272755596).
Almost surely, 213122545511191 is an apocalyptic number.
13122545511191 is a deficient number, since it is larger than the sum of its proper divisors (1).
13122545511191 is an equidigital number, since it uses as much as digits as its factorization.
13122545511191 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 54000, while the sum is 41.
The spelling of 13122545511191 in words is "thirteen trillion, one hundred twenty-two billion, five hundred forty-five million, five hundred eleven thousand, one hundred ninety-one".
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