1312300023001 has 4 divisors (see below), whose sum is σ = 1431600025104. Its totient is φ = 1193000020900.

The previous prime is 1312300022947. The next prime is 1312300023019. The reversal of 1312300023001 is 1003200032131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1312300023001 - 2¹¹ = 1312300020953 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1312300023401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59650001035 + ... + 59650001056.

It is an arithmetic number, because the mean of its divisors is an integer number (357900006276).

Almost surely, 2^{1312300023001} is an apocalyptic number.

1312300023001 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1312300023001 is a deficient number, since it is larger than the sum of its proper divisors (119300002103).

1312300023001 is a wasteful number, since it uses less digits than its factorization.

1312300023001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 119300002102.

The product of its (nonzero) digits is 108, while the sum is 16.

Adding to 1312300023001 its reverse (1003200032131), we get a palindrome (2315500055132).

The spelling of 1312300023001 in words is "one trillion, three hundred twelve billion, three hundred million, twenty-three thousand, one".