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13123001153 = 90714468579
BaseRepresentation
bin11000011100011000…
…10001101101000001
31020212120020112022202
430032030101231001
5203333442014103
610010103242545
7643125445403
oct141614215501
936776215282
1013123001153
115624656aa9
122662a49455
131311a09952
148c6c26b73
1551c14b988
hex30e311b41

13123001153 has 4 divisors (see below), whose sum is σ = 13137470640. Its totient is φ = 13108531668.

The previous prime is 13123001119. The next prime is 13123001161. The reversal of 13123001153 is 35110032131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 35110032131 = 93377376003.

It is a cyclic number.

It is not a de Polignac number, because 13123001153 - 28 = 13123000897 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13123001953) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7233383 + ... + 7235196.

It is an arithmetic number, because the mean of its divisors is an integer number (3284367660).

Almost surely, 213123001153 is an apocalyptic number.

It is an amenable number.

13123001153 is a deficient number, since it is larger than the sum of its proper divisors (14469487).

13123001153 is an equidigital number, since it uses as much as digits as its factorization.

13123001153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14469486.

The product of its (nonzero) digits is 270, while the sum is 20.

Adding to 13123001153 its reverse (35110032131), we get a palindrome (48233033284).

The spelling of 13123001153 in words is "thirteen billion, one hundred twenty-three million, one thousand, one hundred fifty-three".

Divisors: 1 907 14468579 13123001153