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1312300122323 is a prime number
BaseRepresentation
bin10011000110001011001…
…011101100000011010011
311122110021110012102000012
4103012023023230003103
5133000042312403243
62442510133545135
7163545006664331
oct23061313540323
94573243172005
101312300122323
114665a8231143
121923ba7a51ab
13969984a0628
1447730dacb51
1524208bcad18
hex1318b2ec0d3

1312300122323 has 2 divisors, whose sum is σ = 1312300122324. Its totient is φ = 1312300122322.

The previous prime is 1312300122319. The next prime is 1312300122373. The reversal of 1312300122323 is 3232210032131.

It is a weak prime.

It is an emirp because it is prime and its reverse (3232210032131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1312300122323 - 22 = 1312300122319 is a prime.

It is a super-2 number, since 2×13123001223232 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1312300122373) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656150061161 + 656150061162.

It is an arithmetic number, because the mean of its divisors is an integer number (656150061162).

Almost surely, 21312300122323 is an apocalyptic number.

1312300122323 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312300122323 is an equidigital number, since it uses as much as digits as its factorization.

1312300122323 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 1312300122323 its reverse (3232210032131), we get a palindrome (4544510154454).

The spelling of 1312300122323 in words is "one trillion, three hundred twelve billion, three hundred million, one hundred twenty-two thousand, three hundred twenty-three".