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1312300313029 is a prime number
BaseRepresentation
bin10011000110001011001…
…100011010100111000101
311122110021110120002121101
4103012023030122213011
5133000042340004104
62442510142020101
7163545011420326
oct23061314324705
94573243502541
101312300313029
114665a8351452
121923ba877631
1396998539384
144773101c44d
1524208c175a4
hex1318b31a9c5

1312300313029 has 2 divisors, whose sum is σ = 1312300313030. Its totient is φ = 1312300313028.

The previous prime is 1312300313011. The next prime is 1312300313039. The reversal of 1312300313029 is 9203130032131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1105393596129 + 206906716900 = 1051377^2 + 454870^2 .

It is a cyclic number.

It is not a de Polignac number, because 1312300313029 - 213 = 1312300304837 is a prime.

It is a super-2 number, since 2×13123003130292 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1312300312988 and 1312300313006.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1312300313039) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656150156514 + 656150156515.

It is an arithmetic number, because the mean of its divisors is an integer number (656150156515).

Almost surely, 21312300313029 is an apocalyptic number.

It is an amenable number.

1312300313029 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312300313029 is an equidigital number, since it uses as much as digits as its factorization.

1312300313029 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2916, while the sum is 28.

The spelling of 1312300313029 in words is "one trillion, three hundred twelve billion, three hundred million, three hundred thirteen thousand, twenty-nine".