131230101113101 has 4 divisors (see below), whose sum is σ = 132891241633600. Its totient is φ = 129568960592604.

The previous prime is 131230101113009. The next prime is 131230101113117. The reversal of 131230101113101 is 101311101032131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131230101113101 - 2⁹ = 131230101112589 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131230101113161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 830570260131 + ... + 830570260288.

It is an arithmetic number, because the mean of its divisors is an integer number (33222810408400).

Almost surely, 2^{131230101113101} is an apocalyptic number.

It is an amenable number.

131230101113101 is a deficient number, since it is larger than the sum of its proper divisors (1661140520499).

131230101113101 is an equidigital number, since it uses as much as digits as its factorization.

131230101113101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1661140520498.

The product of its (nonzero) digits is 54, while the sum is 19.

Adding to 131230101113101 its reverse (101311101032131), we get a palindrome (232541202145232).

The spelling of 131230101113101 in words is "one hundred thirty-one trillion, two hundred thirty billion, one hundred one million, one hundred thirteen thousand, one hundred one".