Base | Representation |
---|---|
bin | 1011111011110111000001… |
… | …1101111111110110010011 |
3 | 1201110112210021021122121212 |
4 | 2332331300131333312103 |
5 | 3210001412033014141 |
6 | 43524343430410335 |
7 | 2523051320352332 |
oct | 276756035776623 |
9 | 51415707248555 |
10 | 13123012001171 |
11 | 41aa490181986 |
12 | 157b3b22009ab |
13 | 742657b996a7 |
14 | 33522b3b9d19 |
15 | 17b55dca22eb |
hex | bef7077fd93 |
13123012001171 has 2 divisors, whose sum is σ = 13123012001172. Its totient is φ = 13123012001170.
The previous prime is 13123012001167. The next prime is 13123012001243. The reversal of 13123012001171 is 17110021032131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13123012001171 - 22 = 13123012001167 is a prime.
It is not a weakly prime, because it can be changed into another prime (13123012004171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561506000585 + 6561506000586.
It is an arithmetic number, because the mean of its divisors is an integer number (6561506000586).
Almost surely, 213123012001171 is an apocalyptic number.
13123012001171 is a deficient number, since it is larger than the sum of its proper divisors (1).
13123012001171 is an equidigital number, since it uses as much as digits as its factorization.
13123012001171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 252, while the sum is 23.
The spelling of 13123012001171 in words is "thirteen trillion, one hundred twenty-three billion, twelve million, one thousand, one hundred seventy-one".
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