13123021112011 has 4 divisors (see below), whose sum is σ = 13123162859224. Its totient is φ = 13122879364800.

The previous prime is 13123021111973. The next prime is 13123021112041. The reversal of 13123021112011 is 11021112032131.

13123021112011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13123021112011 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13123021112011.

It is not an unprimeable number, because it can be changed into a prime (13123021112041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 70734645 + ... + 70919926.

It is an arithmetic number, because the mean of its divisors is an integer number (3280790714806).

Almost surely, 2^{13123021112011} is an apocalyptic number.

13123021112011 is a deficient number, since it is larger than the sum of its proper divisors (141747213).

13123021112011 is an equidigital number, since it uses as much as digits as its factorization.

13123021112011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 141747212.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 13123021112011 its reverse (11021112032131), we get a palindrome (24144133144142).

The spelling of 13123021112011 in words is "thirteen trillion, one hundred twenty-three billion, twenty-one million, one hundred twelve thousand, eleven".