Base | Representation |
---|---|
bin | 11000011100011000… |
… | …10111000100101101 |
3 | 1020212120021122111102 |
4 | 30032030113010231 |
5 | 203333443220044 |
6 | 10010103532445 |
7 | 643125566465 |
oct | 141614270455 |
9 | 36776248442 |
10 | 13123023149 |
11 | 5624671585 |
12 | 2662a5a125 |
13 | 1311a16972 |
14 | 8c6c30ba5 |
15 | 51c15324e |
hex | 30e31712d |
13123023149 has 2 divisors, whose sum is σ = 13123023150. Its totient is φ = 13123023148.
The previous prime is 13123023103. The next prime is 13123023167. The reversal of 13123023149 is 94132032131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13031820649 + 91202500 = 114157^2 + 9550^2 .
It is an emirp because it is prime and its reverse (94132032131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13123023149 - 28 = 13123022893 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13123023449) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561511574 + 6561511575.
It is an arithmetic number, because the mean of its divisors is an integer number (6561511575).
Almost surely, 213123023149 is an apocalyptic number.
It is an amenable number.
13123023149 is a deficient number, since it is larger than the sum of its proper divisors (1).
13123023149 is an equidigital number, since it uses as much as digits as its factorization.
13123023149 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3888, while the sum is 29.
The spelling of 13123023149 in words is "thirteen billion, one hundred twenty-three million, twenty-three thousand, one hundred forty-nine".
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