13123040201 has 4 divisors (see below), whose sum is σ = 13209947904. Its totient is φ = 13036132500.

The previous prime is 13123040173. The next prime is 13123040221. The reversal of 13123040201 is 10204032131.

13123040201 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13123040201 - 2²² = 13118845897 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 13123040201.

It is not an unprimeable number, because it can be changed into a prime (13123040221) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43453625 + ... + 43453926.

It is an arithmetic number, because the mean of its divisors is an integer number (3302486976).

Almost surely, 2^13123040201 is an apocalyptic number.

It is an amenable number.

13123040201 is a deficient number, since it is larger than the sum of its proper divisors (86907703).

13123040201 is an equidigital number, since it uses as much as digits as its factorization.

13123040201 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 86907702.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 13123040201 its reverse (10204032131), we get a palindrome (23327072332).

The spelling of 13123040201 in words is "thirteen billion, one hundred twenty-three million, forty thousand, two hundred one".