Base | Representation |
---|---|
bin | 11000011100011000… |
… | …11100001101001101 |
3 | 1020212120022201100002 |
4 | 30032030130031031 |
5 | 203333444403143 |
6 | 10010104214045 |
7 | 643126015001 |
oct | 141614341515 |
9 | 36776281302 |
10 | 13123044173 |
11 | 5624686358 |
12 | 2662a6a325 |
13 | 1311a233c5 |
14 | 8c6c38701 |
15 | 51c1595b8 |
hex | 30e31c34d |
13123044173 has 2 divisors, whose sum is σ = 13123044174. Its totient is φ = 13123044172.
The previous prime is 13123044169. The next prime is 13123044257. The reversal of 13123044173 is 37144032131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9025380004 + 4097664169 = 95002^2 + 64013^2 .
It is an emirp because it is prime and its reverse (37144032131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13123044173 - 22 = 13123044169 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13123044113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561522086 + 6561522087.
It is an arithmetic number, because the mean of its divisors is an integer number (6561522087).
Almost surely, 213123044173 is an apocalyptic number.
It is an amenable number.
13123044173 is a deficient number, since it is larger than the sum of its proper divisors (1).
13123044173 is an equidigital number, since it uses as much as digits as its factorization.
13123044173 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 29.
The spelling of 13123044173 in words is "thirteen billion, one hundred twenty-three million, forty-four thousand, one hundred seventy-three".
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