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131230454113 = 1111930041283
BaseRepresentation
bin111101000110111110…
…0011101000101100001
3110112201200020210100101
41322031330131011201
54122224444012423
6140141512022401
712324004312063
oct1721574350541
9415650223311
10131230454113
1150722196560
1221524991a01
13c4b4a9c8a5
1464cca85733
153630db77ad
hex1e8df1d161

131230454113 has 4 divisors (see below), whose sum is σ = 143160495408. Its totient is φ = 119300412820.

The previous prime is 131230454093. The next prime is 131230454123. The reversal of 131230454113 is 311454032131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131230454113 - 217 = 131230323041 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131230454123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5965020631 + ... + 5965020652.

It is an arithmetic number, because the mean of its divisors is an integer number (35790123852).

Almost surely, 2131230454113 is an apocalyptic number.

It is an amenable number.

131230454113 is a deficient number, since it is larger than the sum of its proper divisors (11930041295).

131230454113 is a wasteful number, since it uses less digits than its factorization.

131230454113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11930041294.

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 131230454113 its reverse (311454032131), we get a palindrome (442684486244).

The spelling of 131230454113 in words is "one hundred thirty-one billion, two hundred thirty million, four hundred fifty-four thousand, one hundred thirteen".

Divisors: 1 11 11930041283 131230454113