Base | Representation |
---|---|
bin | 111101000110111110… |
… | …0011101000101100001 |
3 | 110112201200020210100101 |
4 | 1322031330131011201 |
5 | 4122224444012423 |
6 | 140141512022401 |
7 | 12324004312063 |
oct | 1721574350541 |
9 | 415650223311 |
10 | 131230454113 |
11 | 50722196560 |
12 | 21524991a01 |
13 | c4b4a9c8a5 |
14 | 64cca85733 |
15 | 3630db77ad |
hex | 1e8df1d161 |
131230454113 has 4 divisors (see below), whose sum is σ = 143160495408. Its totient is φ = 119300412820.
The previous prime is 131230454093. The next prime is 131230454123. The reversal of 131230454113 is 311454032131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 131230454113 - 217 = 131230323041 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131230454123) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5965020631 + ... + 5965020652.
It is an arithmetic number, because the mean of its divisors is an integer number (35790123852).
Almost surely, 2131230454113 is an apocalyptic number.
It is an amenable number.
131230454113 is a deficient number, since it is larger than the sum of its proper divisors (11930041295).
131230454113 is a wasteful number, since it uses less digits than its factorization.
131230454113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11930041294.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 131230454113 its reverse (311454032131), we get a palindrome (442684486244).
The spelling of 131230454113 in words is "one hundred thirty-one billion, two hundred thirty million, four hundred fifty-four thousand, one hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •