Base | Representation |
---|---|
bin | 10011000110001011011… |
… | …100111000111101011011 |
3 | 11122110021202200111122001 |
4 | 103012023130320331123 |
5 | 133000044441203033 |
6 | 2442510414341431 |
7 | 163545063215125 |
oct | 23061334707533 |
9 | 4573252614561 |
10 | 1312304631643 |
11 | 4665aa831055 |
12 | 1924001ba877 |
13 | 969993bbc75 |
14 | 47731824215 |
15 | 242092bbe7d |
hex | 1318b738f5b |
1312304631643 has 4 divisors (see below), whose sum is σ = 1312536616200. Its totient is φ = 1312072647088.
The previous prime is 1312304631623. The next prime is 1312304631667. The reversal of 1312304631643 is 3461364032131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1312304631643 - 225 = 1312271077211 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1312304631623) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 115983793 + ... + 115995106.
It is an arithmetic number, because the mean of its divisors is an integer number (328134154050).
Almost surely, 21312304631643 is an apocalyptic number.
1312304631643 is a deficient number, since it is larger than the sum of its proper divisors (231984557).
1312304631643 is an equidigital number, since it uses as much as digits as its factorization.
1312304631643 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 231984556.
The product of its (nonzero) digits is 93312, while the sum is 37.
Adding to 1312304631643 its reverse (3461364032131), we get a palindrome (4773668663774).
The spelling of 1312304631643 in words is "one trillion, three hundred twelve billion, three hundred four million, six hundred thirty-one thousand, six hundred forty-three".
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