Base | Representation |
---|---|
bin | 111101000110111111… |
… | …0111101001101011111 |
3 | 110112201201111010000212 |
4 | 1322031332331031133 |
5 | 4122230131004413 |
6 | 140141534043035 |
7 | 12324013013201 |
oct | 1721576751537 |
9 | 415651433025 |
10 | 131231109983 |
11 | 507225a42a6 |
12 | 2152504947b |
13 | c4b4c6c28c |
14 | 64ccbb6771 |
15 | 3630e96ca8 |
hex | 1e8dfbd35f |
131231109983 has 2 divisors, whose sum is σ = 131231109984. Its totient is φ = 131231109982.
The previous prime is 131231109979. The next prime is 131231110061. The reversal of 131231109983 is 389901132131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131231109983 - 22 = 131231109979 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 131231109983.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131231109973) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65615554991 + 65615554992.
It is an arithmetic number, because the mean of its divisors is an integer number (65615554992).
Almost surely, 2131231109983 is an apocalyptic number.
131231109983 is a deficient number, since it is larger than the sum of its proper divisors (1).
131231109983 is an equidigital number, since it uses as much as digits as its factorization.
131231109983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 34992, while the sum is 41.
The spelling of 131231109983 in words is "one hundred thirty-one billion, two hundred thirty-one million, one hundred nine thousand, nine hundred eighty-three".
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