Base | Representation |
---|---|
bin | 111101000110111111… |
… | …1000010010101111001 |
3 | 110112201201112011212022 |
4 | 1322031333002111321 |
5 | 4122230132143001 |
6 | 140141534324225 |
7 | 12324013131365 |
oct | 1721577022571 |
9 | 415651464768 |
10 | 131231131001 |
11 | 50722609073 |
12 | 21525059675 |
13 | c4b4c78a09 |
14 | 64ccbc02a5 |
15 | 3630e9d11b |
hex | 1e8dfc2579 |
131231131001 has 2 divisors, whose sum is σ = 131231131002. Its totient is φ = 131231131000.
The previous prime is 131231130991. The next prime is 131231131039. The reversal of 131231131001 is 100131132131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 127717605376 + 3513525625 = 357376^2 + 59275^2 .
It is a cyclic number.
It is not a de Polignac number, because 131231131001 - 214 = 131231114617 is a prime.
It is not a weakly prime, because it can be changed into another prime (131231131061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65615565500 + 65615565501.
It is an arithmetic number, because the mean of its divisors is an integer number (65615565501).
Almost surely, 2131231131001 is an apocalyptic number.
It is an amenable number.
131231131001 is a deficient number, since it is larger than the sum of its proper divisors (1).
131231131001 is an equidigital number, since it uses as much as digits as its factorization.
131231131001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 131231131001 its reverse (100131132131), we get a palindrome (231362263132).
It can be divided in two parts, 131 and 231131001, that added together give a palindrome (231131132).
The spelling of 131231131001 in words is "one hundred thirty-one billion, two hundred thirty-one million, one hundred thirty-one thousand, one".
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