13123210001003 has 4 divisors (see below), whose sum is σ = 13123956971160. Its totient is φ = 13122463030848.

The previous prime is 13123210000963. The next prime is 13123210001071. The reversal of 13123210001003 is 30010001232131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13123210001003 is a prime.

It is a super-2 number, since 2×13123210001003² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13123210001093) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 373458725 + ... + 373493862.

It is an arithmetic number, because the mean of its divisors is an integer number (3280989242790).

Almost surely, 2^{13123210001003} is an apocalyptic number.

13123210001003 is a deficient number, since it is larger than the sum of its proper divisors (746970157).

13123210001003 is an equidigital number, since it uses as much as digits as its factorization.

13123210001003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 746970156.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 13123210001003 its reverse (30010001232131), we get a palindrome (43133211233134).

The spelling of 13123210001003 in words is "thirteen trillion, one hundred twenty-three billion, two hundred ten million, one thousand, three".