Base | Representation |
---|---|
bin | 11101110101101011101000… |
… | …000000111001001001010111 |
3 | 122012122200120020201200112002 |
4 | 131311223220000321021113 |
5 | 114200102244231411132 |
6 | 1143035144055145515 |
7 | 36433136211051422 |
oct | 3565535000711127 |
9 | 565580506650462 |
10 | 131232323310167 |
11 | 388a635231a6a2 |
12 | 1287585367529b |
13 | 582c20267c111 |
14 | 245996d50a9b9 |
15 | 10289c1d36262 |
hex | 775ae8039257 |
131232323310167 has 2 divisors, whose sum is σ = 131232323310168. Its totient is φ = 131232323310166.
The previous prime is 131232323310061. The next prime is 131232323310211. The reversal of 131232323310167 is 761013323232131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131232323310167 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 131232323310167.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131232323318167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65616161655083 + 65616161655084.
It is an arithmetic number, because the mean of its divisors is an integer number (65616161655084).
Almost surely, 2131232323310167 is an apocalyptic number.
131232323310167 is a deficient number, since it is larger than the sum of its proper divisors (1).
131232323310167 is an equidigital number, since it uses as much as digits as its factorization.
131232323310167 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81648, while the sum is 38.
Adding to 131232323310167 its reverse (761013323232131), we get a palindrome (892245646542298).
The spelling of 131232323310167 in words is "one hundred thirty-one trillion, two hundred thirty-two billion, three hundred twenty-three million, three hundred ten thousand, one hundred sixty-seven".
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