Base | Representation |
---|---|
bin | 11101110101101011101101… |
… | …111110110000011000110111 |
3 | 122012122200211020002110012122 |
4 | 131311223231332300120313 |
5 | 114200103000343211203 |
6 | 1143035202032510155 |
7 | 36433141534653332 |
oct | 3565535576603067 |
9 | 565580736073178 |
10 | 131232423413303 |
11 | 388a63a3881663 |
12 | 128758810ab35b |
13 | 582c21a32a844 |
14 | 245997c927619 |
15 | 10289caa0b538 |
hex | 775aedfb0637 |
131232423413303 has 2 divisors, whose sum is σ = 131232423413304. Its totient is φ = 131232423413302.
The previous prime is 131232423413291. The next prime is 131232423413347. The reversal of 131232423413303 is 303314324232131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131232423413303 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131232423413393) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65616211706651 + 65616211706652.
It is an arithmetic number, because the mean of its divisors is an integer number (65616211706652).
Almost surely, 2131232423413303 is an apocalyptic number.
131232423413303 is a deficient number, since it is larger than the sum of its proper divisors (1).
131232423413303 is an equidigital number, since it uses as much as digits as its factorization.
131232423413303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 93312, while the sum is 35.
Adding to 131232423413303 its reverse (303314324232131), we get a palindrome (434546747645434).
The spelling of 131232423413303 in words is "one hundred thirty-one trillion, two hundred thirty-two billion, four hundred twenty-three million, four hundred thirteen thousand, three hundred three".
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