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13123255031483 is a prime number
BaseRepresentation
bin1011111011110111111011…
…1101000101011010111011
31201110120102012120212112112
42332331332331011122323
53210002411242001413
643524423511402535
72523060331155452
oct276757675053273
951416365525475
1013123255031483
1141aa5a5385183
12157b45b68344b
1374269633b8cc
1433525179db99
1517b5752ab2a8
hexbef7ef456bb

13123255031483 has 2 divisors, whose sum is σ = 13123255031484. Its totient is φ = 13123255031482.

The previous prime is 13123255031461. The next prime is 13123255031519. The reversal of 13123255031483 is 38413055232131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13123255031483 - 212 = 13123255027387 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13123255031483.

It is not a weakly prime, because it can be changed into another prime (13123255031983) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561627515741 + 6561627515742.

It is an arithmetic number, because the mean of its divisors is an integer number (6561627515742).

Almost surely, 213123255031483 is an apocalyptic number.

13123255031483 is a deficient number, since it is larger than the sum of its proper divisors (1).

13123255031483 is an equidigital number, since it uses as much as digits as its factorization.

13123255031483 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 259200, while the sum is 41.

The spelling of 13123255031483 in words is "thirteen trillion, one hundred twenty-three billion, two hundred fifty-five million, thirty-one thousand, four hundred eighty-three".