Base | Representation |
---|---|
bin | 1011111011110111111011… |
… | …1101000101011011011111 |
3 | 1201110120102012120212120212 |
4 | 2332331332331011123133 |
5 | 3210002411242002034 |
6 | 43524423511403035 |
7 | 2523060331155533 |
oct | 276757675053337 |
9 | 51416365525525 |
10 | 13123255031519 |
11 | 41aa5a5385206 |
12 | 157b45b68347b |
13 | 74269633b929 |
14 | 33525179dbc3 |
15 | 17b5752ab2ce |
hex | bef7ef456df |
13123255031519 has 2 divisors, whose sum is σ = 13123255031520. Its totient is φ = 13123255031518.
The previous prime is 13123255031483. The next prime is 13123255031563. The reversal of 13123255031519 is 91513055232131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13123255031519 - 212 = 13123255027423 is a prime.
It is a super-2 number, since 2×131232550315192 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13123255051519) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561627515759 + 6561627515760.
It is an arithmetic number, because the mean of its divisors is an integer number (6561627515760).
Almost surely, 213123255031519 is an apocalyptic number.
13123255031519 is a deficient number, since it is larger than the sum of its proper divisors (1).
13123255031519 is an equidigital number, since it uses as much as digits as its factorization.
13123255031519 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 121500, while the sum is 41.
The spelling of 13123255031519 in words is "thirteen trillion, one hundred twenty-three billion, two hundred fifty-five million, thirty-one thousand, five hundred nineteen".
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