Base | Representation |
---|---|
bin | 1011111011111000000111… |
… | …0001111001110110101101 |
3 | 1201110120112111210002001122 |
4 | 2332332001301321312231 |
5 | 3210003010410312143 |
6 | 43524432323350325 |
7 | 2523061445106053 |
oct | 276760161716655 |
9 | 51416474702048 |
10 | 13123302432173 |
11 | 41aa61a10aaaa |
12 | 157b4735223a5 |
13 | 7426a30c6b5b |
14 | 335257bbc1d3 |
15 | 17b579520c68 |
hex | bef81c79dad |
13123302432173 has 2 divisors, whose sum is σ = 13123302432174. Its totient is φ = 13123302432172.
The previous prime is 13123302432077. The next prime is 13123302432179. The reversal of 13123302432173 is 37123420332131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12093235766089 + 1030066666084 = 3477533^2 + 1014922^2 .
It is a cyclic number.
It is not a de Polignac number, because 13123302432173 - 220 = 13123301383597 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13123302432179) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561651216086 + 6561651216087.
It is an arithmetic number, because the mean of its divisors is an integer number (6561651216087).
Almost surely, 213123302432173 is an apocalyptic number.
It is an amenable number.
13123302432173 is a deficient number, since it is larger than the sum of its proper divisors (1).
13123302432173 is an equidigital number, since it uses as much as digits as its factorization.
13123302432173 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54432, while the sum is 35.
The spelling of 13123302432173 in words is "thirteen trillion, one hundred twenty-three billion, three hundred two million, four hundred thirty-two thousand, one hundred seventy-three".
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