13123304013173 has 2 divisors, whose sum is σ = 13123304013174. Its totient is φ = 13123304013172.

The previous prime is 13123304013137. The next prime is 13123304013221. The reversal of 13123304013173 is 37131040332131.

Together with previous prime (13123304013137) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7195822345009 + 5927481668164 = 2682503^2 + 2434642^2 .

It is a cyclic number.

It is not a de Polignac number, because 13123304013173 - 2¹² = 13123304009077 is a prime.

It is a super-2 number, since 2×13123304013173² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13123304013103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561652006586 + 6561652006587.

It is an arithmetic number, because the mean of its divisors is an integer number (6561652006587).

Almost surely, 2^{13123304013173} is an apocalyptic number.

It is an amenable number.

13123304013173 is a deficient number, since it is larger than the sum of its proper divisors (1).

13123304013173 is an equidigital number, since it uses as much as digits as its factorization.

13123304013173 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13608, while the sum is 32.

The spelling of 13123304013173 in words is "thirteen trillion, one hundred twenty-three billion, three hundred four million, thirteen thousand, one hundred seventy-three".