13123305441151 has 4 divisors (see below), whose sum is σ = 13123343928472. Its totient is φ = 13123266953832.

The previous prime is 13123305441091. The next prime is 13123305441203. The reversal of 13123305441151 is 15114450332131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13123305441151 - 2¹³ = 13123305432959 is a prime.

It is a super-2 number, since 2×13123305441151² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13123305421151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18727581 + ... + 19415686.

It is an arithmetic number, because the mean of its divisors is an integer number (3280835982118).

Almost surely, 2^{13123305441151} is an apocalyptic number.

13123305441151 is a deficient number, since it is larger than the sum of its proper divisors (38487321).

13123305441151 is an equidigital number, since it uses as much as digits as its factorization.

13123305441151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38487320.

The product of its (nonzero) digits is 21600, while the sum is 34.

Adding to 13123305441151 its reverse (15114450332131), we get a palindrome (28237755773282).

The spelling of 13123305441151 in words is "thirteen trillion, one hundred twenty-three billion, three hundred five million, four hundred forty-one thousand, one hundred fifty-one".