Search a number
-
+
131233132023000 = 23353767772712697
BaseRepresentation
bin11101110101101100011000…
…001101111000110011011000
3122012122202122121110112222020
4131311230120031320303120
5114200110423244214000
61143035400224454440
736433165231023660
oct3565543015706330
9565582577415866
10131233132023000
11388a6727871607
1212875a3a47a420
13582c301092a17
142459a08aa31a0
151028a1cd2eba0
hex775b18378cd8

131233132023000 has 512 divisors, whose sum is σ = 469312618844160. Its totient is φ = 29908282060800.

The previous prime is 131233132022939. The next prime is 131233132023013. The reversal of 131233132023000 is 320231332131.

It is a super-2 number, since 2×1312331320230002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 10335752652 + ... + 10335765348.

It is an arithmetic number, because the mean of its divisors is an integer number (916626208680).

Almost surely, 2131233132023000 is an apocalyptic number.

131233132023000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131233132023000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (234656309422080).

131233132023000 is an abundant number, since it is smaller than the sum of its proper divisors (338079486821160).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131233132023000 is a wasteful number, since it uses less digits than its factorization.

131233132023000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14132 (or 14118 counting only the distinct ones).

The product of its (nonzero) digits is 1944, while the sum is 24.

Adding to 131233132023000 its reverse (320231332131), we get a palindrome (131553363355131).

The spelling of 131233132023000 in words is "one hundred thirty-one trillion, two hundred thirty-three billion, one hundred thirty-two million, twenty-three thousand".