Base | Representation |
---|---|
bin | 11101110101101100011100… |
… | …100001110000111010010111 |
3 | 122012122202211122112202120101 |
4 | 131311230130201300322113 |
5 | 114200111100302424143 |
6 | 1143035411330514531 |
7 | 36433200066520531 |
oct | 3565543441607227 |
9 | 565582748482511 |
10 | 131233204342423 |
11 | 388a6764677227 |
12 | 12875a5a735a47 |
13 | 582c313064191 |
14 | 2459a1452a851 |
15 | 1028a24367b4d |
hex | 775b1c870e97 |
131233204342423 has 2 divisors, whose sum is σ = 131233204342424. Its totient is φ = 131233204342422.
The previous prime is 131233204342379. The next prime is 131233204342441. The reversal of 131233204342423 is 324243402332131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131233204342423 - 225 = 131233170787991 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131233204342223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65616602171211 + 65616602171212.
It is an arithmetic number, because the mean of its divisors is an integer number (65616602171212).
Almost surely, 2131233204342423 is an apocalyptic number.
131233204342423 is a deficient number, since it is larger than the sum of its proper divisors (1).
131233204342423 is an equidigital number, since it uses as much as digits as its factorization.
131233204342423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 248832, while the sum is 37.
Adding to 131233204342423 its reverse (324243402332131), we get a palindrome (455476606674554).
The spelling of 131233204342423 in words is "one hundred thirty-one trillion, two hundred thirty-three billion, two hundred four million, three hundred forty-two thousand, four hundred twenty-three".
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