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13123332003 = 34374444001
BaseRepresentation
bin11000011100011011…
…00010011110100011
31020212120212100011110
430032031202132203
5203334033111003
610010114314403
7643131324105
oct141615423643
936776770143
1013123332003
115624862631
122662b88a03
131311ac4412
148c6cb1575
1551c1b4a03
hex30e3627a3

13123332003 has 4 divisors (see below), whose sum is σ = 17497776008. Its totient is φ = 8748888000.

The previous prime is 13123331989. The next prime is 13123332023. The reversal of 13123332003 is 30023332131.

13123332003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 13123332003 - 24 = 13123331987 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13123332023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2187221998 + ... + 2187222003.

It is an arithmetic number, because the mean of its divisors is an integer number (4374444002).

Almost surely, 213123332003 is an apocalyptic number.

13123332003 is a deficient number, since it is larger than the sum of its proper divisors (4374444005).

13123332003 is an equidigital number, since it uses as much as digits as its factorization.

13123332003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4374444004.

The product of its (nonzero) digits is 972, while the sum is 21.

Adding to 13123332003 its reverse (30023332131), we get a palindrome (43146664134).

The spelling of 13123332003 in words is "thirteen billion, one hundred twenty-three million, three hundred thirty-two thousand, three".

Divisors: 1 3 4374444001 13123332003