Base | Representation |
---|---|
bin | 1011111011111000001110… |
… | …0100110011001010110111 |
3 | 1201110120121121110021210202 |
4 | 2332332003210303022313 |
5 | 3210003041113120401 |
6 | 43524435321111115 |
7 | 2523062262112061 |
oct | 276760344631267 |
9 | 51416547407722 |
10 | 13123332551351 |
11 | 41aa635111a90 |
12 | 157b48162849b |
13 | 7426a9411159 |
14 | 33525bbbc731 |
15 | 17b57bec006b |
hex | bef839332b7 |
13123332551351 has 16 divisors (see below), whose sum is σ = 15069980845440. Its totient is φ = 11302297708320.
The previous prime is 13123332551339. The next prime is 13123332551353. The reversal of 13123332551351 is 15315523332131.
It is a cyclic number.
It is not a de Polignac number, because 13123332551351 - 210 = 13123332550327 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13123332551353) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 39119336 + ... + 39453378.
It is an arithmetic number, because the mean of its divisors is an integer number (941873802840).
Almost surely, 213123332551351 is an apocalyptic number.
13123332551351 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
13123332551351 is a deficient number, since it is larger than the sum of its proper divisors (1946648294089).
13123332551351 is a wasteful number, since it uses less digits than its factorization.
13123332551351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 522046.
The product of its digits is 121500, while the sum is 38.
Adding to 13123332551351 its reverse (15315523332131), we get a palindrome (28438855883482).
The spelling of 13123332551351 in words is "thirteen trillion, one hundred twenty-three billion, three hundred thirty-two million, five hundred fifty-one thousand, three hundred fifty-one".
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