Base | Representation |
---|---|
bin | 1011111011111000010000… |
… | …0101001011101100100111 |
3 | 1201110120122012102120121211 |
4 | 2332332010011023230213 |
5 | 3210003100301243143 |
6 | 43524440223052251 |
7 | 2523062424216415 |
oct | 276760405135447 |
9 | 51416565376554 |
10 | 13123341040423 |
11 | 41aa63998aa49 |
12 | 157b484441087 |
13 | 7426ab0c4083 |
14 | 33525cd8c2b5 |
15 | 17b57caea49d |
hex | bef8414bb27 |
13123341040423 has 4 divisors (see below), whose sum is σ = 13123438537320. Its totient is φ = 13123243543528.
The previous prime is 13123341040409. The next prime is 13123341040427. The reversal of 13123341040423 is 32404014332131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13123341040423 - 221 = 13123338943271 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13123341040427) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 48546265 + ... + 48815842.
It is an arithmetic number, because the mean of its divisors is an integer number (3280859634330).
Almost surely, 213123341040423 is an apocalyptic number.
13123341040423 is a deficient number, since it is larger than the sum of its proper divisors (97496897).
13123341040423 is an equidigital number, since it uses as much as digits as its factorization.
13123341040423 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 97496896.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 13123341040423 its reverse (32404014332131), we get a palindrome (45527355372554).
The spelling of 13123341040423 in words is "thirteen trillion, one hundred twenty-three billion, three hundred forty-one million, forty thousand, four hundred twenty-three".
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