Base | Representation |
---|---|
bin | 1011111011111000010000… |
… | …0101100100011001101011 |
3 | 1201110120122012121201102112 |
4 | 2332332010011210121223 |
5 | 3210003100313012421 |
6 | 43524440225152535 |
7 | 2523062425120421 |
oct | 276760405443153 |
9 | 51416565551375 |
10 | 13123341141611 |
11 | 41aa639a49a78 |
12 | 157b48448b74b |
13 | 7426ab12b14c |
14 | 33525cdb7111 |
15 | 17b57cb1a45b |
hex | bef8416466b |
13123341141611 has 2 divisors, whose sum is σ = 13123341141612. Its totient is φ = 13123341141610.
The previous prime is 13123341141539. The next prime is 13123341141641. The reversal of 13123341141611 is 11614114332131.
It is a strong prime.
It is an emirp because it is prime and its reverse (11614114332131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13123341141611 - 234 = 13106161272427 is a prime.
It is not a weakly prime, because it can be changed into another prime (13123341141641) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561670570805 + 6561670570806.
It is an arithmetic number, because the mean of its divisors is an integer number (6561670570806).
Almost surely, 213123341141611 is an apocalyptic number.
13123341141611 is a deficient number, since it is larger than the sum of its proper divisors (1).
13123341141611 is an equidigital number, since it uses as much as digits as its factorization.
13123341141611 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 5184, while the sum is 32.
Adding to 13123341141611 its reverse (11614114332131), we get a palindrome (24737455473742).
The spelling of 13123341141611 in words is "thirteen trillion, one hundred twenty-three billion, three hundred forty-one million, one hundred forty-one thousand, six hundred eleven".
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