Base | Representation |
---|---|
bin | 1011111011111000010000… |
… | …0101100100100001010111 |
3 | 1201110120122012121202002202 |
4 | 2332332010011210201113 |
5 | 3210003100313021403 |
6 | 43524440225155115 |
7 | 2523062425122023 |
oct | 276760405444127 |
9 | 51416565552082 |
10 | 13123341142103 |
11 | 41aa639a4a385 |
12 | 157b48448ba9b |
13 | 7426ab12b43a |
14 | 33525cdb7383 |
15 | 17b57cb1a688 |
hex | bef84164857 |
13123341142103 has 2 divisors, whose sum is σ = 13123341142104. Its totient is φ = 13123341142102.
The previous prime is 13123341142073. The next prime is 13123341142141. The reversal of 13123341142103 is 30124114332131.
13123341142103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13123341142103 - 26 = 13123341142039 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13123341142903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561670571051 + 6561670571052.
It is an arithmetic number, because the mean of its divisors is an integer number (6561670571052).
Almost surely, 213123341142103 is an apocalyptic number.
13123341142103 is a deficient number, since it is larger than the sum of its proper divisors (1).
13123341142103 is an equidigital number, since it uses as much as digits as its factorization.
13123341142103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 13123341142103 its reverse (30124114332131), we get a palindrome (43247455474234).
The spelling of 13123341142103 in words is "thirteen trillion, one hundred twenty-three billion, three hundred forty-one million, one hundred forty-two thousand, one hundred three".
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