131233440044433 has 8 divisors (see below), whose sum is σ = 175075076046496. Its totient is φ = 87440382036000.

The previous prime is 131233440044419. The next prime is 131233440044489. The reversal of 131233440044433 is 334440044332131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 131233440044433 - 2⁴ = 131233440044417 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131233440044391 and 131233440044400.

It is not an unprimeable number, because it can be changed into a prime (131233440049433) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12144492103 + ... + 12144502908.

It is an arithmetic number, because the mean of its divisors is an integer number (21884384505812).

Almost surely, 2^{131233440044433} is an apocalyptic number.

It is an amenable number.

131233440044433 is a deficient number, since it is larger than the sum of its proper divisors (43841636002063).

131233440044433 is a wasteful number, since it uses less digits than its factorization.

131233440044433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24288996815.

The product of its (nonzero) digits is 497664, while the sum is 39.

Adding to 131233440044433 its reverse (334440044332131), we get a palindrome (465673484376564).

The spelling of 131233440044433 in words is "one hundred thirty-one trillion, two hundred thirty-three billion, four hundred forty million, forty-four thousand, four hundred thirty-three".