13123414252042 has 4 divisors (see below), whose sum is σ = 19685121378066. Its totient is φ = 6561707126020.

The previous prime is 13123414252037. The next prime is 13123414252043. The reversal of 13123414252042 is 24025241432131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 7909768129761 + 5213646122281 = 2812431^2 + 2283341^2 .

It is a junction number, because it is equal to n+sod(n) for n = 13123414251989 and 13123414252007.

It is not an unprimeable number, because it can be changed into a prime (13123414252043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3280853563009 + ... + 3280853563012.

Almost surely, 2^{13123414252042} is an apocalyptic number.

13123414252042 is a deficient number, since it is larger than the sum of its proper divisors (6561707126024).

13123414252042 is an equidigital number, since it uses as much as digits as its factorization.

13123414252042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6561707126023.

The product of its (nonzero) digits is 46080, while the sum is 34.

Adding to 13123414252042 its reverse (24025241432131), we get a palindrome (37148655684173).

The spelling of 13123414252042 in words is "thirteen trillion, one hundred twenty-three billion, four hundred fourteen million, two hundred fifty-two thousand, forty-two".